B bobrossu New member Joined Aug 16, 2017 Messages 29 Aug 27, 2017 #1 Problem: Find all real numbers x such that 25x-8*15x-9x+1=0 Not sure how to start. Steps would be helpful.
Problem: Find all real numbers x such that 25x-8*15x-9x+1=0 Not sure how to start. Steps would be helpful.
B bobrossu New member Joined Aug 16, 2017 Messages 29 Aug 28, 2017 #3 mmm4444bot said: Is this homework? Click to expand... No, just practice for me.
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,250 Aug 28, 2017 #4 bobrossu said: Problem: Find all real numbers x such that 25x-8*15x-9x+1=0 Not sure how to start. Steps would be helpful. Click to expand... \(\displaystyle 25^x - 8*15^x - 9^{x + 1} \ = \ 0\) \(\displaystyle 25^x - 8*(5*3)^x - 9*9^x \ = \ 0\) \(\displaystyle (5^2)^x - 8*(5^x)(3^x) - 9(3^2)^x \ = \ 0\) \(\displaystyle (5^x)^2 - 8*(5^x)(3^x) - 9(3^x)^2 \ = \ 0\) Pick two variables other than x, such as r and t. Let r = \(\displaystyle \ 5^x\). Let t = \(\displaystyle \ 3^x\). \(\displaystyle r^2 - 8rt - 9t^2 \ = \ 0\) Factor that trinomial, set each factor equal to zero, substitute back for what r and t equal in terms of x, and solve for any real values of x. Last edited: Aug 28, 2017
bobrossu said: Problem: Find all real numbers x such that 25x-8*15x-9x+1=0 Not sure how to start. Steps would be helpful. Click to expand... \(\displaystyle 25^x - 8*15^x - 9^{x + 1} \ = \ 0\) \(\displaystyle 25^x - 8*(5*3)^x - 9*9^x \ = \ 0\) \(\displaystyle (5^2)^x - 8*(5^x)(3^x) - 9(3^2)^x \ = \ 0\) \(\displaystyle (5^x)^2 - 8*(5^x)(3^x) - 9(3^x)^2 \ = \ 0\) Pick two variables other than x, such as r and t. Let r = \(\displaystyle \ 5^x\). Let t = \(\displaystyle \ 3^x\). \(\displaystyle r^2 - 8rt - 9t^2 \ = \ 0\) Factor that trinomial, set each factor equal to zero, substitute back for what r and t equal in terms of x, and solve for any real values of x.
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Aug 30, 2017 #5 bobrossu said: … just practice for me. Click to expand... Are you practicing for an upcoming math-placement test?
bobrossu said: … just practice for me. Click to expand... Are you practicing for an upcoming math-placement test?