Marcus-Tullius
New member
- Joined
- Jan 13, 2019
- Messages
- 4
View attachment 10883Hello
I have to proof that
GH || FE when alpha = 45 degrees
View attachment 10883
I don´t have any idea of an approach. So please help.
Thanks in advance.
Hello
I have to proof that
GH || FE when alpha = 45 degrees
View attachment 10883
I don´t have any idea of an approach. So please help.
Thanks in advance.
angleI'm sorry. This picture should be better.
I also have the information that E can be anywhere on BC and F on CD. But E and F cannot be at the same place with another point.
I will try to solve it with the tangent at A, but I would appreciate any other help.
Heads up, pka. The LaTeX code above fails because angle is an auto-linked word, in this forum.… \(\displaystyle m(\angle HAG)=\dfrac{\pi}{4}\) …