Given is the function F(x,y,z) = x2+y3-z.
Determine the Jacobian matrix Dz in P=(1,1,2) using implicit differentiation.
My idea is to calculate ∂z/∂x in P(1,1,2) and ∂z/∂y in P(1,1,2) and then just write it in matrix form.
So,
F(x,y,z)=x2+y3-z=0
∂z/∂x=-((∂F/∂x)/(∂F/∂z))=-(2x/-1)=2x
∂z/∂x in P(1,1,2)=2
∂z/∂y=-((∂F/∂y)/(∂F/∂z))=-(3y2/-1)= 3y2
∂z/∂y in P(1,1,2)=3
Dz (1,1,2) = (∂z/∂x(1,1,2) ∂z/∂y(1,1,2)), Dz is [1 X 2] matrix
Dz (1,1,2) = (2 3)
I checked the result using explicit differentiation and I obtained the same.
But in the book that I use I saw another approach. Namely, as a hint was given this formula:
Dx=f(x°)=-[DyF(x°,y°)]-1DxF(x°,y°)
I don’t understand how this formula can be used in order to calculate Dz.
Any help is appreciated.
Thanks in advance.
Determine the Jacobian matrix Dz in P=(1,1,2) using implicit differentiation.
My idea is to calculate ∂z/∂x in P(1,1,2) and ∂z/∂y in P(1,1,2) and then just write it in matrix form.
So,
F(x,y,z)=x2+y3-z=0
∂z/∂x=-((∂F/∂x)/(∂F/∂z))=-(2x/-1)=2x
∂z/∂x in P(1,1,2)=2
∂z/∂y=-((∂F/∂y)/(∂F/∂z))=-(3y2/-1)= 3y2
∂z/∂y in P(1,1,2)=3
Dz (1,1,2) = (∂z/∂x(1,1,2) ∂z/∂y(1,1,2)), Dz is [1 X 2] matrix
Dz (1,1,2) = (2 3)
I checked the result using explicit differentiation and I obtained the same.
But in the book that I use I saw another approach. Namely, as a hint was given this formula:
Dx=f(x°)=-[DyF(x°,y°)]-1DxF(x°,y°)
I don’t understand how this formula can be used in order to calculate Dz.
Any help is appreciated.
Thanks in advance.