burgerandcheese
Junior Member
- Joined
- Jul 2, 2018
- Messages
- 85
Q: The height in metres of the water in a harbour is given approximately by the formula h = 6 + 3cos(π/6 * t) where t is the time measured in hours from noon. Find an expression for the rate at which the water is rising at time t. When is it rising fastest?
I know how to to the expression, I got dh/dt = -π/2 sin( π/6 * t)
(By the way, is that an expression or an equation?)
So for the second part of the question when finding the time when it rises the fastest how come we can't set dh/dt = 0 and solve for t? I did it like that and I got my answer wrong
I know how to to the expression, I got dh/dt = -π/2 sin( π/6 * t)
(By the way, is that an expression or an equation?)
So for the second part of the question when finding the time when it rises the fastest how come we can't set dh/dt = 0 and solve for t? I did it like that and I got my answer wrong