Question about proofing trigonometry

[manasan]

\(\displaystyle
sin\ 75^\circ = \frac{\sqrt{6}+\sqrt{2}}{4}
\)
I don't know where to start.

 

[MarkFL]

I would begin with:

[MATH]75^{\circ}=45^{\circ}+30^{\circ}[/MATH]
And then apply an angle sum identity for the sine function.

 

[manasan]

I would begin with:

[MATH]75^{\circ}=45^{\circ}+30^{\circ}[/MATH]
And then apply an angle sum identity for the sine function.

Thank You Sir for the hint I literally feel like an idiot for missing that