Presumably, you mean:1/3x + 4/7y = 3
2x + 3y = 15
Presumably, you mean:
(1/3)x + (4/7)y = 3
2x + 3y = 15
No, what you did was to multiply both numerator and denominator of each fraction by 21. That is not what I said. I said to multiply both sides of the equation by 21. (Many students do confuse these ideas.)Trying this I obtain:
(21/69)x + (84/147)y = 3
2x + 3y = 15
I don't know what you can do; but it can be done.Thank you, I have done as instructed.
View attachment 13355
Can I simplify further and solve for the variables?
\(\displaystyle \left\{ \begin{array}{l} 7x + 12y = 63\\2x +3y=15\end{array} \right. \Rightarrow \left\{ \begin{array}{l} 7x + 12y = 63\\-8x -12y=-60\end{array}\right. \)\(\displaystyle \Rightarrow,~~x=-3\)
To frctl, had I not followed this entire thread, I would be tempted to ask "are you serious?"How did pka arrive at:−8x−12y=−60 and x = -3