I really need an answer ASAP !! Conditional-probability

Aetius25

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Joined
Feb 3, 2020
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3
Hello, I really need an answer to this problem as soon as possible, thank you very much (Pardon my mathematical presentation I'm not an expert in maths).

The closest description of the issue can be as the following:

If n represents the number of books in a library, and x represents the number of pages in each book; what is the probability for the following event to occur:

A-E = B-D = 0

Where:

A = 1 + 2 + 3 + ... + n

B =
x1 + x2 + x3 + ... + xn

C = (1+x1) + (2+x2) + (3+x3) + … + (n + xn)

D = ∑ (i+xi) "
The sum of even numbers calculated in C "

E = ∑
(j+xj) "
The sum of odd numbers calculated in C "

Conditions:

x (elements of B) are randomly selected from a finite set of positive integers

x > 2

i
represents the number of even numbers calculated in C

j
represents the number of odd numbers calculated in C

i = j = n/2 (if n = 114 then we should have 57 even numbers and 57 odd numbers in C)

n > 19

n & i & j
are multiples of 19


Example:

Conditional Probability - Example.PNG
 
Hello, I really need an answer to this problem as soon as possible, thank you very much (Pardon my mathematical presentation I'm not an expert in maths).

The closest description of the issue can be as the following:

If n represents the number of books in a library, and x represents the number of pages in each book; what is the probability for the following event to occur:

A-E = B-D = 0

Where:

A = 1 + 2 + 3 + ... + n

B =
x1 + x2 + x3 + ... + xn

C = (1+x1) + (2+x2) + (3+x3) + … + (n + xn)

D = ∑ (i+xi) "
The sum of even numbers calculated in C "

E = ∑
(j+xj) "
The sum of odd numbers calculated in C "

Conditions:

x (elements of B) are randomly selected from a finite set of positive integers

x > 2

i
represents the number of even numbers calculated in C

j
represents the number of odd numbers calculated in C

i = j = n/2 (if n = 114 then we should have 57 even numbers and 57 odd numbers in C)

n > 19

n & i & j
are multiples of 19


Example:

View attachment 16467

Please follow the rules of posting in this forum, as enunciated at:

READ BEFORE POSTING

Please share your work/thoughts about this assignment.
 
Hello, I really need an answer to this problem as soon as possible, thank you very much (Pardon my mathematical presentation I'm not an expert in maths).

The closest description of the issue can be as the following:

If n represents the number of books in a library, and x represents the number of pages in each book; what is the probability for the following event to occur:

A-E = B-D = 0

Where:

A = 1 + 2 + 3 + ... + n

B =
x1 + x2 + x3 + ... + xn

C = (1+x1) + (2+x2) + (3+x3) + … + (n + xn)

D = ∑ (i+xi) "
The sum of even numbers calculated in C "

E = ∑
(j+xj) "
The sum of odd numbers calculated in C "

Conditions:

x (elements of B) are randomly selected from a finite set of positive integers

x > 2

i
represents the number of even numbers calculated in C

j
represents the number of odd numbers calculated in C

i = j = n/2 (if n = 114 then we should have 57 even numbers and 57 odd numbers in C)

n > 19

n & i & j
are multiples of 19


Example:

View attachment 16467
Sorry to point this out, but truly this is a nonsense question.
 
Sorry to point this out, but truly this is a nonsense question.

Can you explain to me how is this nonsense please? the example that I shared is already existing as a fact, this is why I was told to calculate the odds of this kind of events, thank you.
 
Last edited:
pka, This is the full data of the example shared in the post above for more understanding:


ABA-E = B-DDE
65556236062366555
nx(n+xn)(i+xi)(j+xj)
1788
2286288288
3200203203
4176180180
5120125125
6165171171
7206213213
8758383
9129138138
10109119119
11123134134
12111123123
13435656
14526666
1599114114
16128144144
17111128128
18110128128
1998117117
20135155155
21112133133
2278100100
23118141141
24648888
2577102102
26227253253
2793120120
2888116116
29699898
30609090
31346565
32306262
3373106106
34548888
35458080
3683119119
37182219219
3888126126
3975114114
4085125125
41549595
42539595
4389132132
4459103103
45378282
46358181
47388585
48297777
49186767
50459595
5160111111
5249101101
5362115115
5455109109
5578133133
5696152152
57298686
58228080
59248383
60137373
61147575
62117373
63117474
64188282
65127777
66127878
67309797
6852120120
6952121121
7044114114
71289999
7228100100
73209393
7456130130
7540115115
7631107107
7750127127
7840118118
7946125125
8042122122
8129110110
8219101101
8336119119
8425109109
8522107107
8617103103
8719106106
8826114114
8930119119
9020110110
9115106106
9221113113
9311104104
948102102
958103103
9619115115
975102102
988106106
998107107
10011111111
10111112112
1028110110
1033106106
1049113113
1055110110
1064110110
1077114114
1083111111
1096115115
1103113113
1115116116
1124116116
1135118118
1146120120
 
Hello, I really need an answer to this problem as soon as possible, thank you very much (Pardon my mathematical presentation I'm not an expert in maths).

The closest description of the issue can be as the following:

If n represents the number of books in a library, and x represents the number of pages in each book; what is the probability for the following event to occur:

A-E = B-D = 0

Where:

A = 1 + 2 + 3 + ... + n

B =
x1 + x2 + x3 + ... + xn

C = (1+x1) + (2+x2) + (3+x3) + … + (n + xn)

D = ∑ (i+xi) "
The sum of even numbers calculated in C "

E = ∑
(j+xj) "
The sum of odd numbers calculated in C "

Conditions:

x (elements of B) are randomly selected from a finite set of positive integers

x > 2

i
represents the number of even numbers calculated in C

j
represents the number of odd numbers calculated in C

i = j = n/2 (if n = 114 then we should have 57 even numbers and 57 odd numbers in C)

n > 19

n & i & j
are multiples of 19
I think what we need is to figure out what event you are asking about. (You admitted your presentation was bad, so we have to correct it.)

What does A-E = B-D = 0 mean? I would take it to mean A=E and B=D; but in what sense is that an "event"? And are all the "conditions" you list meant to be part of the definition of the event?

Looking at your definitions of A through E (in which many variables appear to have subscripts that you have not formatted as such (despite your heavy use of formatting), it looks like A+B = C, and D and E are evidently meant to be, respectively, sums of the even terms and the odd terms of the sum in C, which I suppose means not the terms with even or odd index, but terms whose values are even or odd. Therefore D+E = C. Am I right? So if A=E, then B=D necessarily.

You've indicated that x is a set of n data points xk, each of which is a positive integer; are they distinct, or can some have the same value? You call them "elements of B"; you mean they are the terms of the sum B (that is, B is the sum of elements of x). But then you say x > 2; what does that mean? (A set of data doesn't have a numerical value.) Possibly you mean that each element of x (that is, each xk) is greater than 2.

But then you say that i and j are each n/2, which means that somehow this "random" set of data is such that exactly half of the numbers "k + xk" are even, and half are odd. How does that happen?

But then looking at the example, you are not consistently using n, i, and j as total numbers of data points, as you'd said, but use each of them as I have used k.

My intention is not to criticize your notation, but to figure out what the event is. What you want might be a lot clearer if you told us what it all means. In terms of books and pages, what is the significance of this event? Why did you choose such an odd "event"? And how are the numbers x selected "randomly"? Are you selecting books with equal probability, or what? In order to have a probability at all, you need a population and a sampling method.

As I work through this, I get the feeling that you have a particular set of numbers and want to say that it is extremely unlikely for the properties you have found to occur. If so, that is a meaningless question, because when you choose a data set first, and then choose an event after the fact, there is no randomness at all. For a look at this issue, if that is the case, you might read this (on my blog, where I discuss past answers on a different site).
 
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