Check y = -6 in the original equation.Probably a stupid question but..in the highlighted step below, what happens to the factored 3?
Does the factored 3 become irrelevant, because we are able to get the y by itself in its final factor?
Why is y=-6 an extraneous solution?
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We divide both sides by 3. 0/3 = 0, so we still have 0 on the left.Probably a stupid question but..in the highlighted step below, what happens to the factored 3?
Does the factored 3 become irrelevant, because we are able to get the y by itself in its final factor?
Another way to think about the 3 is that 3(y+6)(y-4) can be zero only if one of its factors is zero. The factors are 3, (y+6), and (y-4).Probably a stupid question but..in the highlighted step below, what happens to the factored 3?
Does the factored 3 become irrelevant, because we are able to get the y by itself in its final factor?