Probability
Full Member
- Joined
- Jan 26, 2012
- Messages
- 425
I am asked to write;
[MATH]{6x}^{5}{y}^{8}[/MATH] in the form [MATH]{2x^2}{y}\times[/MATH] something
I thought;
[MATH]{2x^2}\times{3x^3}\times{y}\times{y^7}={6x^5}\times{y}\times{y^7}\implies[/MATH][MATH]{6x^5}\times{y^8}[/MATH]
But the solution given says;
[MATH]({2x^2}{y}\times{3x^3}\times{y^7})[/MATH]
If I multiply through by 1 I'll still get my same answer. Is this just another way of writing the solution or is it incomplete?
[MATH]{6x}^{5}{y}^{8}[/MATH] in the form [MATH]{2x^2}{y}\times[/MATH] something
I thought;
[MATH]{2x^2}\times{3x^3}\times{y}\times{y^7}={6x^5}\times{y}\times{y^7}\implies[/MATH][MATH]{6x^5}\times{y^8}[/MATH]
But the solution given says;
[MATH]({2x^2}{y}\times{3x^3}\times{y^7})[/MATH]
If I multiply through by 1 I'll still get my same answer. Is this just another way of writing the solution or is it incomplete?