Grade 12 Calculus - Need help solving an equation (URGENT)

[calculus101]

Hi! Could anyone solve this equation for me?

(lnx)^3 + (x) (3(lnx)^2) (1/x) = 0

Thank you!

 

[tkhunny]

What makes it urgent? Are you sitting for the exam right this moment?

Have you considered the simplification of $$(x) (something) (1/x)$$?

 

[calculus101]

the assignment is due tonight, and I’ve spent days trying to figure it out. I’m not quite sure what you mean by the simplification you suggested.

What makes it urgent? Are you sitting form the exam right this moment?

Have you considered the simplification of $$(x) (something) (1/x)$$?

 

[tkhunny]

It is a sad day for the calculus when algebra gets in your way of learning.

Let's recall the commutative property of multiplication. A*B*C = A*C*B. Yes?

 

[calculus101]

Yes, I recall that. Thanks. But how would rearranging those 3 make a difference? What would be my next step after that? Do I need to move something to the right side of the equation at some point?

 

[pka]

Hi! Could anyone solve this equation for me?
$(\log(x))^3 + (3(\log(x))^2) (1/x)(x) = 0$

Did you notice that it is equivalent to $(\log(x))^3 + (3(\log(x))^2) = 0$ the $x's$ divide off.
One solution is $x=1$.

 

[calculus101]

It is a sad day for the calculus when algebra gets in your way of learning.

Let's recall the commutative property of multiplication. A*B*C = A*C*B. Yes?

Ohh, I see!!! So 1/x • x turns to 1. So then I am left with
So I’m left with

(lnx)^3 + 3(lnx)^2= 0.

 

[calculus101]

Yes, just noticed that from the other reply. Thankyou. Can I ask why ln changed to log? Are they the same thing?

Did you notice that it is equivalent to $(\log(x))^3 + (3(\log(x))^2) = 0$ the $x's$ divide off.
One solution is $x=1$.

 

[mmm4444bot]

Can I ask why ln changed to log? Are they the same thing?

Some people use log(x) to mean ln(x). In this thread, you may read both notations to mean the natural logarithm.

For school assignments, it's best to work with the notation used in your class.