Quant Warrior
New member
- Joined
- May 25, 2020
- Messages
- 28
If x^2 - 5y^2 = 1232, how many pairs are possible for (x,y) ?
1) 2
2) 3
3) 1
4) 0
If there were no "5" before y^2, I could have tried to solve it by breaking x^2-y^2 into (x-y)(x+y).
Like this : (x-y)(x+y) = 1232 . At least I would have made an attempt. Buy I am at a loss as to how to go about that question.
Please enlightenment me with clarity on this.
1) 2
2) 3
3) 1
4) 0
If there were no "5" before y^2, I could have tried to solve it by breaking x^2-y^2 into (x-y)(x+y).
Like this : (x-y)(x+y) = 1232 . At least I would have made an attempt. Buy I am at a loss as to how to go about that question.
Please enlightenment me with clarity on this.