alaskanbullworm
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- Joined
- Jul 16, 2020
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So do you know the limit definition?.....yes
Simple but can’t figure it out....see below
Try using some equal signs.To find f'(1) using the limit definition we must find
Lim as h approaches 0 of [f(1+h) - f(1)]/h for the function 10x^2 - 3
So Lim(h->0) [10(1+h)^2 - 3 - (10*1)^2] - 3]/h
Lim(h->0) [10(1 +2h +h^2) - 3 - (10 - 3)]/h
Lim(h->0) [10 + 20h + 10h^2 - 3 -10 + 3]/h
Lim(x->0) [20h + 10h^2]/h
Lim(x->0) [20 + 10h]
20
ok?
To find f'(1) using the limit definition we must find
Lim as h approaches 0 of [f(1+h) - f(1)]/h for the function 10x^2 - 3
So Lim(h->0) [10(1+h)^2 - 3 - (10*1)^2] - 3]/h ..........................incorrect
should be:
Lim(h->0) [10(1+h)^2 - 3 - {10*(1)^2 - 3}]/h
Lim(h->0) [10(1 +2h +h^2) - 3 - (10 - 3)]/h
Lim(h->0) [10 + 20h + 10h^2 - 3 -10 + 3]/h
Lim(x->0) [20h + 10h^2]/h
Lim(x->0) [20 + 10h]
20
ok?
So do you know the limit definition?
Try using some equal signs.
Also can you please read our guidelines so you know what type of responses to make to students. Thank you.
My bad...I didn't read the TOS prior to answering my first question. Over at Quora, you are supposed to answer student's questions or give hints (your choice)Alaskanbullworm? doctorcheck?
Doctorcheck, I'm not sure how much you have helped Alaskanbullworm. Sure you've given him/her the answer, but do they understand??
Since the OP did not show any "effort" towards solution - we would not know the depth of his/her knowledge.simplify, factor, divide then things will clear up. Ok is that a good hint or was it too much?
OK thanks...I now understand the limits of the help I am to give.Since the OP did not show any "effort" towards solution - we would not know the depth of his/her knowledge.
So the first question to the OP should be "do you know the definition of derivative using limit?
After that is clarified - then the question should be - how can we apply that definition to the current problem?
Then your instruction - simplify, factor, divide then things will clear up - becomes an excellent hint.