Please show us what you have tried and exactly where you are stuck.View attachment 21869 pleas guide me for solve this problem.
Do you know L'Hospital's rule?
sorry noDo you know L'Hospital's rule?
Have you been taught "differentiation"?sorry no
yesHave you been taught "differentiation"?
Then you are ready to learn L'Hopital's rule.
Thank you very much Master. Well, for sureThen you are ready to learn L'Hopital's rule.
So I'll point you towards several videos:
L'Hôpital's rule introduction (video) | Khan Academy
When you are solving a limit, and get 0/0 or ∞/∞, L'Hôpital's rule is the tool you need.www.khanacademy.org
Please let us now if you do not follow something.
Looks good to me.
I am not student. Is my answer not correct?I do not think that the student should use L'Hopital's rule, as she did not learn it in her course yet.
Your numerator is (ax+8)1/3-2. Now if you cube each term you would get (ax+8) - 8 = ax. Now the x in ax will cancel with the x in the denominator.
But how do you get to cube both terms? Use the fact that (y-z)(y2+yz+ z2) = y3 - z3.
Now your numerator is in the form (y-z), so just multiply the numerator and denominator by (y2+yz+ z2)
Thanks a lot master.Yes, your results for a and b are correct.