K know New member Joined May 24, 2020 Messages 22 Oct 23, 2020 #1 Solve the matrix equation: Ax = B A = (1 3 -2 -6) B = (14 7 -28 14) Can anyone explain me how I can do that equation?
Solve the matrix equation: Ax = B A = (1 3 -2 -6) B = (14 7 -28 14) Can anyone explain me how I can do that equation?
D Deleted member 4993 Guest Oct 23, 2020 #2 know said: Solve the matrix equation: Ax = B A = (1 3 -2 -6) B = (14 7 -28 14) Can anyone explain me how I can do that equation? Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem.
know said: Solve the matrix equation: Ax = B A = (1 3 -2 -6) B = (14 7 -28 14) Can anyone explain me how I can do that equation? Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Oct 23, 2020 #3 You must know how matrix multiplication works. \(\left[ {\begin{array}{*{20}{c}} 1&3 \\ { - 2}&{ - 6} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} a&b \\ c&d \end{array}} \right] = \)\( \left[ {\begin{array}{*{20}{c}} {14}&7 \\ { - 28}&{14}\end{array}} \right]\) \(\left\{ \begin{gathered} a+3c=14 \hfill \\ b+3d=7 \hfill \\ -2a-6c=-28 \hfill \\ -2b-6d=14 \hfill \\ \end{gathered} \right\}\)
You must know how matrix multiplication works. \(\left[ {\begin{array}{*{20}{c}} 1&3 \\ { - 2}&{ - 6} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} a&b \\ c&d \end{array}} \right] = \)\( \left[ {\begin{array}{*{20}{c}} {14}&7 \\ { - 28}&{14}\end{array}} \right]\) \(\left\{ \begin{gathered} a+3c=14 \hfill \\ b+3d=7 \hfill \\ -2a-6c=-28 \hfill \\ -2b-6d=14 \hfill \\ \end{gathered} \right\}\)