How Many Betting Tickets Need to Fill to Win Jackpot?

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mathhead!

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John has started betting career.
In order to win a big jackpot, John needs to guess right 7 times in one ticket. His average score is 3 right of 7.
How many tickets John needs to fill until he will win a jackpot?
 
It's betting. It's gambling. The HOUSE can't make money unless the overall payoff is in their favor. There is no such thing as "...will win a jackpot". Depends on how the machines are set. Depends on the skill of the player in a particular game. Numbers don't have memory. If there were a solution to this problem, all casinos would be out of business in a moment.

Whence came this problem? Not from a regular text book I'm hoping.
 
This is just basic game theory, ever heard? Question wasn't about house's edge, gambling etc.
John can guess right 42,86% of time (3 of 7) in average.

Out of the record, there are professional sport bettors who make their living by sports betting, so no need to act "smart".
 
mathhead! said:
This is just basic game theory, ever heard? Question wasn't about house's edge, gambling etc.
John can guess right 42,86% of time (3 of 7) in average.

Out of the record, there are professional sport bettors who make their living by sports betting, so no need to act "smart".
Click to expand...
If "the house" was not making money, even the "professional sports bettors" would be out of the business. Of course there are some winners, even some relatively consistent winners. Also of course, these are the ones that get advertised.

I was thinking more of a lotto. Sorry about that. If you could just buy enough tickets until you won, no one would tolerate that.

Binomial(7,3/7)

p(0) = 0.003
p(1) = 0.025
p(2) = 0.099
p(3) = 0.220
p(4) = 0.294
p(5) = 0.235
p(6) = 0.104
p(7) = 0.020 <== So, 50? This would create the EXPECTATION of one 7-pick winner. It would NOT ensure a 7-pick winner.
 
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