Nickirusso
New member
- Joined
- Jan 4, 2021
- Messages
- 3
Let f(x)=10x+14−15e^(x) Then the equation of the tangent line to the graph of f(x) at the point (0,−1) is given by y=mx+b for
M = ???
B = -1
M = ???
B = -1
Hi Nickirusso. Please use the given symbols m and b (capital letters are different symbols).M = ???
B = -1
The equation that I have done to find m IsHi Nickirusso. Please use the given symbols m and b (capital letters are different symbols).
m = the slope of the tangent line
The first derivative of function f outputs the slope of the tangent line at x. Please show us your attempt at finding the first derivative of f(x).
b = -1 is correct. Very good reasoning.
?
It looks like you are just finding f(0) and dropping the constant term. That is not how you find the slope.The equation that I have done to find m Is
10(0) - 15e ^(0) and I get - 15 and I firmly believe that this is the correct slope but it appears that the answer of -15 is incorrect. Thank you for your reply!
Hi Nickirusso. That is not an equation. (All equations contain an equals sign.) We call that an 'expression'.The equation … to find m Is 10(0) - 15e ^(0)…