If I were to solve this problem, for my assignment, I would start with:
You are asked to find "x" for a given range of y.are you converting it to exponential ?
Have you studied " logarithmic function " ?im still not following you
I'm baffled. It says a=1; why are you setting it to 2? I'm also curious why they call the base of the logarithm "base" (or "bse"?) rather than using a proper variable?Yes.. I know how to convert log to exp and vice versa but I don't understand the (BX) and what value do I plug in " BSE " ?
f (x) = a log base (bx)... if a = 2;
y = 2 log base (bx)
inverse:
x = 2 log base (by)
x/2 = log base ( by )
base"x/2 = by
f -1 (x) = base"x/2 (by) .... is this correct so far ?
Could you enter the correct function?I'm baffled. It says a=1; why are you setting it to 2? I'm also curious why they call the base of the logarithm "base" (or "bse"?) rather than using a proper variable?
As I understand the problem, they are defining a function [imath]f(x) = \log_c(bx)[/imath], and telling you that [imath]f(2) = 0[/imath] and [imath]f(3) = 1[/imath]. Plug those two pairs in to obtain two equations in variables b and c, and solve for them. Then you'll know the function.
Please make an attempt, so we can see what you have learned and where you need help. I have told you how to start.Could you enter the correct function?
Also, we are using bse in my classroom.
Thank you
Don't use the same variable name, b, for both the base and the coefficient. This is why I used c; if you want to use the name "base" for this variable, do so, though it is quite odd.
In what you did here, what happened to x? And why didn't you replace x and y with 2 and 0, then 3 and 1, as I suggested?