mathshelpplease
New member
- Joined
- Oct 5, 2021
- Messages
- 25
Hello, I have been struggling with this problem and got this far, but I am not sure how to proceed in actually solving to show that f(x) = 0
Any help would be much appreciated.
Consider the function:
[math]f(x)=(1-1/4x)exp(-x^2+5x-6)[/math]Show the following holds:
I have calculated that
[math]f'(x)=((2x^2-13x+19)exp(-x^2+5x-6))/4[/math]and from that, that if f(x) = 0, [math]x=(13+sqrt17)/4[/math]or [math]x=(13-sqrt17)/4[/math]
but am unsure how to show that this means that x tends to infinity
Any help would be much appreciated.
Consider the function:
[math]f(x)=(1-1/4x)exp(-x^2+5x-6)[/math]Show the following holds:
I have calculated that
[math]f'(x)=((2x^2-13x+19)exp(-x^2+5x-6))/4[/math]and from that, that if f(x) = 0, [math]x=(13+sqrt17)/4[/math]or [math]x=(13-sqrt17)/4[/math]
but am unsure how to show that this means that x tends to infinity