I maybe understand a) but don't get the rest.
If you at least understand what (a) means, then the notation is probably not the issue.Hi, sorry if this is the wrong category but I'm not too sure what the notation in this question means. I maybe understand a) but don't get the rest.
I know binomial theorem and basic sigma notation (like Σ n(n+1) kind of thing), but I'm not sure what the a_k x^k means and how to apply that to (2-x)^n. is a_k a constant?If you at least understand what (a) means, then the notation is probably not the issue.
Have you considered expanding the summand in (b), and using the results of (a)?
But first, it sounds like you haven't actually solved any of (a). I'm guessing that you've learned the binomial theorem; what else have you learned that might be useful? The more you tell us, specifically, about what you do and don't know, the better we can help.
If you at least understand what (a) means, then the notation is probably not the issue.
I know binomial theorem and basic sigma notation (like Σ n(n+1) kind of thing), but I'm not sure what the a_k x^k means and how to apply that to (2-x)^n. is a_k a constant?
What I mean by I sort of understand a) is that I understood it as sub in x=1 and prove with induction, which is probably incorrect
The [imath]a_k[/imath] are the coefficients in the expansion. Yes, they are constants. It may help if you work out the details for a specific value of n, such as 3 or 4. What is the expansion of [imath]2-x)^3[/imath]? What are the coefficients? What do the three parts of (a) mean in that specific case?Sorry, I just realised that I misread. I meant that I maybe understood part ai, and was asking for help on aii, not part b.
This reminds me that I intended to add that induction is not necessarily required for (a i); I affirmed that mostly on the assumption that induction may be what the OP is expected (or at least expects) to use.After following @Dr.Peterson advice can you complete and post the solution for a.i) ?
Also, are you familiar with derivatives?