Arthur and Bert hit a target with probabilities of 4/5 and 7/10 respectively.
Find the probability that;
1. they both hit the target
2. they both miss the target
3. at LEAST one of them hits the target.
Please help, I don't know how to solve it, here is what I tried.
(hit,hit)
(4/5 * 7/10) = 14/25
(miss,miss)
(1/5 * 3/10) = 3/50
(hit, miss)
(4/5 * 3/10) = 6/25
(miss,hit)
(1/5 * 7/10) = 7/50
I'm lost. Please help. Thanks.
Find the probability that;
1. they both hit the target
2. they both miss the target
3. at LEAST one of them hits the target.
Please help, I don't know how to solve it, here is what I tried.
(hit,hit)
(4/5 * 7/10) = 14/25
(miss,miss)
(1/5 * 3/10) = 3/50
(hit, miss)
(4/5 * 3/10) = 6/25
(miss,hit)
(1/5 * 7/10) = 7/50
I'm lost. Please help. Thanks.
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