Hi Everyone!
How do I find the coordinates of symmetry of the graph of:
[math]\frac{(x+a)(x-1)}{x-a}\\[/math]
I've started by dividing the numerator by the denominator, perhaps getting an oblique asymptote?
I resulted in the answer of: [math]x+(2a-1) + \frac{-2a-2a^2}{x-a}\\[/math]I don't think this is correct... so any help would really be appreciated. Thank you!!
How do I find the coordinates of symmetry of the graph of:
[math]\frac{(x+a)(x-1)}{x-a}\\[/math]
I've started by dividing the numerator by the denominator, perhaps getting an oblique asymptote?
I resulted in the answer of: [math]x+(2a-1) + \frac{-2a-2a^2}{x-a}\\[/math]I don't think this is correct... so any help would really be appreciated. Thank you!!