Divide what exactly?I would carefully divide by a-1 and by a+1.
What Steven G means isI honestly have no idea how to solve this, but I tried. Any advice? View attachment 32521View attachment 32522
what about a-1=0What Steven G means is
[imath]a(a - 1)x \geq a - 1[/imath]
Divide both sides by a - 1. Be careful with the cases where a - 1 > 0 and a - 1 < 0. If, for example, a - 1 > 0 can a + 1 < 0?
-Dan
Can you divide 0?what about a-1=0
Isn't it obvious? Divide the inequality by a-1. Divide the other inequality by a+1.Divide what exactly?
what i mean is that by diving by a-1 i am introducing a condition that a-1 can't be 0, but what if a is 1?Can you divide 0?
can you explain why? what is the goal?Isn't it obvious? Divide the inequality by a-1. Divide the other inequality by a+1.
Do that case separately. I did suggest that you divide carefully.what i mean is that by diving by a-1 i am introducing a condition that a-1 can't be 0, but what if a is 1?
i usually avoid diving because it can eliminate a certain solutionDo that case separately. I did suggest that you divide carefully.
Yes. If I say a>1, a has to also >-1Under I, you wrote if a>1, then a>-1. Is that what you meant to write?
x>-6Can you please solve this simple inequality: -2x<12
It seemed that I saw somewhere in your work you failed to interchange the inequality sign.x>-6