The statement is not true for an arbitrary function [imath]f[/imath]. For example if [imath]f(x) = x[/imath] then k =2, p = 8 and [imath]k^2+p^2 = 68[/imath], which is not divisible by 5.Not sure how to start this question.
If f(k/2)=1 and f(p+1)=9. Show that k^2+p^2 is divisible by 5.
Any help would be appreciated. Thanks.
I'm curious to see the actual problem, and it might help other readers.Ah. Now I see. I have been given a function and a point on the graph so I can work it out now. Sometimes I just need a nudge.
Thanks. So the actual question can be phrased like this:Sorry I didn’t think to include it all. The info at the start of the question is as follows.
The graph of the function f(x) =a^x+b, where x is a member of the real numbers and includes the points A(1, -5) and B(2, -3)
Then it asks you to prove the statement as in my initial question.
What is the domain of each of those numbers?Not sure how to start this question.
If f(k/2)=1 and f(p+1)=9. Show that k^2+p^2 is divisible by 5.
Any help would be appreciated. Thanks.