we have eight positive integers in a row. Starting from the third, each is the sum of the two numbers before it. If the eighth number is 2017, what is the largest possible value of the first one?
I am approaching the question as follow :
1st a
2nd b
3rd a+b
4th a + 2b
5th 2a + 3b
6th 3a + 5b
7th 5a + 8b
8th 8a + 13b =2017
How do we solve from one equation only?
appreciate the help
I am approaching the question as follow :
1st a
2nd b
3rd a+b
4th a + 2b
5th 2a + 3b
6th 3a + 5b
7th 5a + 8b
8th 8a + 13b =2017
How do we solve from one equation only?
appreciate the help