Please offer your thoughts - so that we know where to begin?Can anyone offer any thoughts on this problem please?
Well, we don't know that both sides are equal; we want to prove they are. So you can't take this as given.What i have tried so far:
siny =1/x and cos y = - sqrt(1-1/x^2)
That's basically what he's doing, but calling the angle y.If I were to solve this problem, I would substitute
x = sec (Θ)
You found that y is in quadrant IV. What quadrant will -y be in? Therefore, what is the sign of cos(-y)?I think we would pick the negative sqrt because we need to cos y to be positive?