[SOLVED BUT CANNOT DELETE THREAD] finding the Galois Group G(Q(2,3)/Q)\mathbb{Q(\sqrt{2}, \sqrt3)}/\mathbb{Q})

MathNugget

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I am trying to find the Galois Group G(Q(2,3)/Q)\mathbb{Q(\sqrt{2}, \sqrt3)}/\mathbb{Q}). That means, I have to find the automorphisms ϕ:Q(2,3)Q(2,3)\phi: \mathbb{Q(\sqrt{2}, \sqrt3)} \rightarrow \mathbb{Q(\sqrt{2}, \sqrt3)}, for which ϕ(x)=x,xQ\phi(x)=x, \forall x \in \mathbb{Q}.
Let's say K=Q(2,3)\mathbb{Q(\sqrt{2}, \sqrt3)}.

I am fairly certain that all elements of K can be written as a+b2+c3+d6a + b\sqrt2 +c\sqrt3 + d\sqrt 6, a,b,c,dQa, b, c, d \in \mathbb{Q}.
I know that if K=Q(c)K=\mathbb{Q}(\sqrt{c}), there are 2 automorphisms: a+bcabca+b\sqrt{c} \rightarrow a-b\sqrt{c} and identity. (let's say here that c is positive, and isn't the square of an integer or rational, so that c\sqrt{c} is irrational but not complex.
I also know that if K=RK=\mathbb{R} has just 1 automorphism satisfying this, the identity.

I have read the wikipedia page on Galois groups, there is a bit of info about it, but it doesn't satisfy my question. Would this field have 2^3 automorphisms? a±b2±c3±d6a \pm b\sqrt2 \pm c\sqrt3 \pm d\sqrt6?
 
Nevermind, found it...https://math.stackexchange.com/questions/455067/computing-galois-group-of-mathbbq-sqrt2-sqrt3-mathbbq
How can I delete thread?
 
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