Find the gradient of the tangent to the curve y = (2x-1)/x[sup:1x8n67k8]2[/sup:1x8n67k8]+3 at the point where the curve cuts the x-axis.
I've found the dy/dx already but I'm not sure what I should do next.
Given that y= (2x+3)[sup:1rlan0cz]5[/sup:1rlan0cz](x+2)[sup:1rlan0cz]8[/sup:1rlan0cz], find the value of dy/dx when x=-1?
I'm confused with this question: where and when do I put -1 in?
Differentiate (a[sup:34a4ir4u]2[/sup:34a4ir4u]+x[sup:34a4ir4u]2[/sup:34a4ir4u]){sqrt(a[sup:34a4ir4u]2[/sup:34a4ir4u]-x[sup:34a4ir4u]2[/sup:34a4ir4u])} with respect to x?
Can I simplify {sqrt(a[sup:34a4ir4u]2[/sup:34a4ir4u]-x[sup:34a4ir4u]2[/sup:34a4ir4u])} this instead of differentiating it? If...
Differentiate 2x (sqrt(3x-1))[sup:9ycku2t5]5[/sup:9ycku2t5] with respect to x?
First I found out that du/dx = 2 and dv/dx = 2x/(sqrt(2x[sup:9ycku2t5]2[/sup:9ycku2t5]+3))
Then I multiplied du/dx with v and u with dv/dx......... and I'm stuck with the fractions and powers. Can someone help?
In the expansion of (3+4x)[sup:33uo6uz1]n[/sup:33uo6uz1], the coefficients of x[sup:33uo6uz1]4[/sup:33uo6uz1] and x[sup:33uo6uz1]5[/sup:33uo6uz1] are in the ratio 5:16. Find the value of n.
Do I do like this: [[n(n-1)(n-2)(n-3)(n-4)]/(5!)] / [[n(n-1)(n-2)(n-3)] /(4!)] = 16/5 ? If yes then what...
If the coefficients of x[sup:2dv5pkzn]k[/sup:2dv5pkzn] and x[sup:2dv5pkzn]k+1[/sup:2dv5pkzn] in the expansion of (2+3x)[sup:2dv5pkzn]19[/sup:2dv5pkzn] are equal, find k
I've got the answer through the tables book but am wondering if there is a way to calculate it manually. PLEASE help.
Find, in ascending powers of x, the first three terms of (1+kx)[sup:262hd7sh]4[/sup:262hd7sh](1-4x)[sup:262hd7sh]3[/sup:262hd7sh].
I've found the first 3 terms of each:
(1+kx)[sup:262hd7sh]4[/sup:262hd7sh] = 1 + 4kx + 6k[sup:262hd7sh]2[/sup:262hd7sh]x[sup:262hd7sh]2[/sup:262hd7sh] and...
The expansion of (1+kx)[sup:2mpidhus]n[/sup:2mpidhus], where n is a positive integer, is 1 + 8x + 120k[sup:2mpidhus]2[/sup:2mpidhus]x[sup:2mpidhus]2[/sup:2mpidhus] + hx[sup:2mpidhus]3[/sup:2mpidhus] +......
Calculate the values of n, h and k
I've already done...
In my question
Find, in ascending powers of x, the first 3 terms in the expansion of (2+3x-4x[sup:2czwrjur]2[/sup:2czwrjur])[sup:2czwrjur]5[/sup:2czwrjur]
Well I arranged it into [(2+3x)[sup:2czwrjur]5[/sup:2czwrjur] +(-4x[sup:2czwrjur]2[/sup:2czwrjur])[sup:2czwrjur]5[/sup:2czwrjur]]. Then I'm...
In my question:
Differentiate 1/sqrt(a[sup:2uwf4kg9]2[/sup:2uwf4kg9] - 2x) with respect to x. I've changed (a[sup:2uwf4kg9]2[/sup:2uwf4kg9] -2x) to (a[sup:2uwf4kg9]2[/sup:2uwf4kg9] -2x)[sup:2uwf4kg9]-1/2[/sup:2uwf4kg9]. What next?
In my question:
Find the gradient of the curve y= 2+ [12/(3x-4)[sup:1nprnysn]2[/sup:1nprnysn]] at the point (2,5)
Do I differentiate 2 together with the fraction?
The function g(x) = p sin x+q where p < 0 has a maximum value of 10 and a minimum value of -4. Find the values of p and q
I know that for sin graphs, p + q = maximum and -p + q = minimum, but how about this? I've tried reversing the unknowns and switching positive and negative signs but am...
If sin 50[sup:cp0szzn7]o[/sup:cp0szzn7] = p, then how do I express cos 50 in terms of p? So far I've figured out that it's in quadrant 1, meaning it is positive.
The gradient of the curve y= ax[sup:8lu77rre]2[/sup:8lu77rre] + bx at the points x=1 and x=3 are -2 and 10 respectively. Find the values of a and b
Do I subsitute the values of x given to create 2 simultaneous equations or do I differentiate the equation first. HELP PLEASE!
In my question:
Calculate the gradient of the curve y= (x-4)/x when the point is y=3
Do I differentiate the equation of the curve first or do I subsitute y= 3 first. Thx.
The points P, Q and R are on level ground such that Q is due north of P. The bearing of R from P is 018[sup:mloc695q]o[/sup:mloc695q] and the bearing of R from Q is 063[sup:mloc695q]o[/sup:mloc695q]. Given that the vertical post XQ is 32m, and that the length of PQ is 250m, calculate the angle...
A, B, C and D are four points on horizontal ground with D due east of A. Given that AB = 70m, BC = 80m, CD = 110m and AD = 190 m, and that the angle B is 115[sup:3h7gf2bz]o[/sup:3h7gf2bz], calculate angle ADC and the bearing of B from A
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