Sorry, i copied the table from the document i got the exercise from, which contained commas. I hope it didn't cause to much confusion.
so the function then becomes y = 3 + 2*x^(1.23266), and it doesn't really correspond to the table on the later values. should this function be considered...
I have done some calculations now.
y= C + a*x^n
3 = C proven when x = 0
y = 3 + a*x^n
5 = 3 + a*1^n makes a = 2
8.7 = 3 + 2*2^n
ln((8.7-3)/ (5/3)) = n*ln(2)
n = 0.354
so the function should be y = 3 + 2*x^(0.35), but this function grows to slowly for the table. Can you see anything...
hello!
I have been given a task where i should use logarithmic linearization to find a functions exponent with the base of x. So i need to make an exponential function which corresponds to the values of the table below.
The function should look something like y = C + axn, and after the...
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