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  1. W

    Help with finding equation through logarithmic linearization

    Ha i see now. Thanks so much! :D
  2. W

    Help with finding equation through logarithmic linearization

    Sorry, i copied the table from the document i got the exercise from, which contained commas. I hope it didn't cause to much confusion. so the function then becomes y = 3 + 2*x^(1.23266), and it doesn't really correspond to the table on the later values. should this function be considered...
  3. W

    Help with finding equation through logarithmic linearization

    I have done some calculations now. y= C + a*x^n 3 = C proven when x = 0 y = 3 + a*x^n 5 = 3 + a*1^n makes a = 2 8.7 = 3 + 2*2^n ln((8.7-3)/ (5/3)) = n*ln(2) n = 0.354 so the function should be y = 3 + 2*x^(0.35), but this function grows to slowly for the table. Can you see anything...
  4. W

    Help with finding equation through logarithmic linearization

    Edit: I think it's called log-linear analysis in english, but i have a hard time applying in to this table.
  5. W

    Help with finding equation through logarithmic linearization

    hello! I have been given a task where i should use logarithmic linearization to find a functions exponent with the base of x. So i need to make an exponential function which corresponds to the values of the table below. The function should look something like y = C + axn, and after the...
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