Waddlingduck
New member
- Joined
- Jan 11, 2014
- Messages
- 5
hello!
I have been given a task where i should use logarithmic linearization to find a functions exponent with the base of x. So i need to make an exponential function which corresponds to the values of the table below.
The function should look something like y = C + axn, and after the logarithmic linearization it looks like ln(y-c) = ln(a) + n*ln(x) which is a linear function. my teacher told me that the "n" is the incline of the funtion and is therefore the exponent I'm searching for.
the thing is, I dont know how to do logarithmic linearization when i have a zero value in the table. I've tried to simply ignore that value but that gives me the wrong function that doesn't correspond to the table.
Any help? my teacher told me that this exercise is extremely easy if you know how to do it, but I have been here trying for about 5 hours.
x 0,0 1,0 2,0 5,0 7,0 10,0
y 3,0 5,0 8,7 25,4 40,0 66,2
I have been given a task where i should use logarithmic linearization to find a functions exponent with the base of x. So i need to make an exponential function which corresponds to the values of the table below.
The function should look something like y = C + axn, and after the logarithmic linearization it looks like ln(y-c) = ln(a) + n*ln(x) which is a linear function. my teacher told me that the "n" is the incline of the funtion and is therefore the exponent I'm searching for.
the thing is, I dont know how to do logarithmic linearization when i have a zero value in the table. I've tried to simply ignore that value but that gives me the wrong function that doesn't correspond to the table.
Any help? my teacher told me that this exercise is extremely easy if you know how to do it, but I have been here trying for about 5 hours.
x 0,0 1,0 2,0 5,0 7,0 10,0
y 3,0 5,0 8,7 25,4 40,0 66,2