T tsh44 Junior Member Joined Sep 4, 2005 Messages 67 Dec 15, 2005 #1 I am also haivng toruble with this problem sec x = 2 csc 2 where would I start? should I change them to cos and sin?
I am also haivng toruble with this problem sec x = 2 csc 2 where would I start? should I change them to cos and sin?
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Dec 15, 2005 #2 You may mean sec x = 2 csc(x) In which case, changing them to cos and sin would be a great place start.
You may mean sec x = 2 csc(x) In which case, changing them to cos and sin would be a great place start.
T tsh44 Junior Member Joined Sep 4, 2005 Messages 67 Dec 15, 2005 #3 Srry for the typo. Where would i go next. I have 1/cosx- 2 (1/sinx) = 0 but I don't see anything out of this.
Srry for the typo. Where would i go next. I have 1/cosx- 2 (1/sinx) = 0 but I don't see anything out of this.
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Dec 15, 2005 #4 \(\displaystyle \L \frac{1}{\cos{x}} = \frac{2}{\sin{x}}\) What would happen if we multiplied both sides by sin(x)?
\(\displaystyle \L \frac{1}{\cos{x}} = \frac{2}{\sin{x}}\) What would happen if we multiplied both sides by sin(x)?
T tsh44 Junior Member Joined Sep 4, 2005 Messages 67 Dec 15, 2005 #5 thanks i got tan x= 2 1.11, 4.25
i got tan x= 2