Suppose that [imath]s~\&~t[/imath] are real numbers and that [imath]z=s+ti[/imath].
Then for #4, [imath]z+16=(s+16)+ti[/imath] so that [imath]|z+16|=\sqrt{(s+16)^2+t^2}~\&~4|z+1|=4\sqrt{(s+1)^2+t^2}[/imath]
#6 [imath]\dfrac{-i}{x-yi}=\dfrac{4+7i}{5-3i}[/imath] is equivalent to [imath](-i)(5-3i)=(x-yi)(4+7i)[/imath].
Recall that the real parts are equal and that the imagery parts are equal.
[imath][/imath][imath][/imath][imath][/imath]
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