2 log { base 2 } of x - log { base 2 } of [(x/2) - 1] - 4 =

[Secret]

Hiii

it's me again

can someone help me and tell me if my answer is correct in this ?!


2 log { base 2 } of x - log { base 2 } of [(x/2) - 1] - 4 = 0

log { base 2 } of (x^2) - log { base 2 } of [(x/2) - 1] = 4

log { base 2 } of {(x^2)/[(x/2) - 1]} = 4

{(x^2)/[(x/2) - 1]} = (4^2)

{(x^2)/[(x/2) - 1]} = 16

(x^2) = 16 [(x/2) - 1]

(x^2) = 16x - 16

(x^2) - 8x + 16 = 0

(x - 4) (x - 4) = 0

so

x = 4

is my answer correct ?!

 

[morson]

Yes it is. Check in future, by substituting your solution into the equation. Especially with these logarithm questions.

 

[Secret]

ok

thanks

next time I will check by substituting

and thanks again