G ginny1029 Junior Member Joined Apr 25, 2009 Messages 53 Jun 7, 2009 #1 does this look right? 2x + 5 sqrt x = 0 5 sqrt x = -2x (5 sqrt x) ^2 = (-2x) ^2 25x = 4x^2 0+ 4x^2 - 25x 0 = x(4x - 25) x = 0 or 0 = 4x - 25 divide by 4x by 4 and -25 by 4 x = 25/4
does this look right? 2x + 5 sqrt x = 0 5 sqrt x = -2x (5 sqrt x) ^2 = (-2x) ^2 25x = 4x^2 0+ 4x^2 - 25x 0 = x(4x - 25) x = 0 or 0 = 4x - 25 divide by 4x by 4 and -25 by 4 x = 25/4
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 Jun 7, 2009 #2 2x + 5 sqrt x = 0 5 sqrt x = -2x (5 sqrt x) ^2 = (-2x) ^2 25x = 4x^2 0+ 4x^2 - 25x 0 = x(4x - 25) x = 0 or 0 = 4x - 25 divide by 4x by 4 and -25 by 4 x = 25/4 Click to expand... Plug your answers back into the original equation. Do they both work? One does not.
2x + 5 sqrt x = 0 5 sqrt x = -2x (5 sqrt x) ^2 = (-2x) ^2 25x = 4x^2 0+ 4x^2 - 25x 0 = x(4x - 25) x = 0 or 0 = 4x - 25 divide by 4x by 4 and -25 by 4 x = 25/4 Click to expand... Plug your answers back into the original equation. Do they both work? One does not.