G
Guest
Guest
we forgot how to multiply mixed number by a whole number. I just need to see acouple of lines of how to work the problem and I'll remember
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There are two ways to look at this.
1) Change the mixed number to an improper fraction and then multiply.
e.g., multiply 8 1/3 by 6
Change 8 1/3 to an improper by multiplying 3*8 and adding this result to the numerator, 1. Write this over the denominator, 3. You get:
25/3
Multiply this by 6 to get:
6*25/3 = 50
2) Rewrite 8 1/3 as 8 + 1/3. Multiply this by 6 using the Distributive Law:
6(8 + 1/3) = 6*8 + 6* 1/3 = 48 + 2 = 50
Hope that helps...
Steve
1) Change the mixed number to an improper fraction and then multiply.
e.g., multiply 8 1/3 by 6
Change 8 1/3 to an improper by multiplying 3*8 and adding this result to the numerator, 1. Write this over the denominator, 3. You get:
25/3
Multiply this by 6 to get:
6*25/3 = 50
2) Rewrite 8 1/3 as 8 + 1/3. Multiply this by 6 using the Distributive Law:
6(8 + 1/3) = 6*8 + 6* 1/3 = 48 + 2 = 50
Hope that helps...
Steve
Hello, bobbys!
I think Gene's second method is the easiest.
Example: \(\displaystyle \L\,2\frac{1}{3}\,\times\,4\)
Change both numbers into fractions: \(\displaystyle \L\,\frac{7}{3}\,\times\,\frac{4}{1}\)
Multiply: \(\displaystyle \L\,\frac{28}{3}\)
Convert to a mixed number: \(\displaystyle \L\,9\frac{1}{3}\)
I think Gene's second method is the easiest.
Example: \(\displaystyle \L\,2\frac{1}{3}\,\times\,4\)
Change both numbers into fractions: \(\displaystyle \L\,\frac{7}{3}\,\times\,\frac{4}{1}\)
Multiply: \(\displaystyle \L\,\frac{28}{3}\)
Convert to a mixed number: \(\displaystyle \L\,9\frac{1}{3}\)