[math]\Pr\left(\frac{\bar{X}-\bar{Y}-2}{\sqrt{13}} >c\right)=\Pr\left(Z >\frac{c-2}{\sqrt{13}}\right) =1-\Pr\left(Z \le\frac{c-2}{\sqrt{13}}\right)=0.5[/math]Using a standard normal distribution table or calculator, can you continue?
Thank you![math]\Pr\left(\frac{\bar{X}-\bar{Y}-2}{\sqrt{13}} >c\right)=\Pr\left(Z >\frac{c-2}{\sqrt{13}}\right) =1-\Pr\left(Z \le\frac{c-2}{\sqrt{13}}\right)=0.5[/math]Using a standard normal distribution table or calculator, can you continue?
There's a typo in post#2, here's a redo:[math]\Pr\left(\frac{\bar{X}-\bar{Y}-2}{\sqrt{13}} >c\right)=\Pr\left(Z >\frac{c-2}{\sqrt{13}}\right) =1-\Pr\left(Z \le\frac{c-2}{\sqrt{13}}\right)=0.5[/math]Using a standard normal distribution table or calculator, can you continue?