A alpepe New member Joined Dec 6, 2006 Messages 8 Dec 11, 2006 #1 I need some help please!!! The question is: . . .5x = -3(x + 4) +28 Here is what I did: . . .5x = -3(x + 4) + 28 . . .5x = -3x - 12 + 28 This is where im stuck. Do I subtract the twelve? Anything will help. Thank you!
I need some help please!!! The question is: . . .5x = -3(x + 4) +28 Here is what I did: . . .5x = -3(x + 4) + 28 . . .5x = -3x - 12 + 28 This is where im stuck. Do I subtract the twelve? Anything will help. Thank you!
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,579 Dec 11, 2006 #2 Yes, you would subtract the 12 from the 28. Then you would probably want to add 3x to either side of the equation, and then divide through by 8. Eliz.
Yes, you would subtract the 12 from the 28. Then you would probably want to add 3x to either side of the equation, and then divide through by 8. Eliz.
