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Thread: How to factor this expression?

  1. #1

    How to factor this expression?

    I understand how to do basic factoring like ax^2 + bx + c but I don't understand how to do factoring with more variables then those in the equation. For example: x2+14x+49y

  2. #2
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    Quote Originally Posted by ace7269 View Post
    I understand how to do basic factoring like ax^2 + bx + c but I don't understand how to do factoring with more variables then those in the equation. For example: x2+14x+49y
    Why don't you provide an actual problem in its entirety and show what you have tried.

    By the way, you have given expressions, not equations. You factor expressions.

    And it is quite feasible to factor the given expression: [tex]x^2 + 14x + 49 - y = (x + 7)^2 - y.[/tex]

  3. #3

    Factoring

    Okay, here is a full problem. Factor the expression ay+a6y6. Simplify your answer as much as possible.

    Please trust me I have tried to work these out but I can't figure it out. Should I be using the ax^2 + bx + c expression? I just don't understand where to even start with these expressions. I'm not asking for anyone to do my homework I'm just trying to figure out these steps so I can do these kinds of problems on the exam tomorrow.

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    Quote Originally Posted by ace7269 View Post
    Okay, here is a full problem. Factor the expression ay+a6y6. Simplify your answer as much as possible.

    Please trust me I have tried to work these out but I can't figure it out. Should I be using the ax^2 + bx + c expression? I just don't understand where to even start with these expressions. I'm not asking for anyone to do my homework I'm just trying to figure out these steps so I can do these kinds of problems on the exam tomorrow.
    [tex]ax^2 + bx + c[/tex] is the standard form for a quadratic in one variable.

    A quadratic in standard form can be factored using the quadratic formula, but it pertains only to that special case.

    All factoring means is to restate an expression as a product of expressions. The most common way to do that is to look for common factors in the expression.

    Is your expression [tex]ay + a^6y^6?[/tex] If so, you should see that ay is a common factor and [tex]ay + a^6y^6 = ay(1 + a^5y^5).[/tex]

    If your expression is [tex]ay + a * 6 * y * 6,[/tex] then ay is again a common factor and [tex]ay - a * 6 * y * 6 = ay(1 + 6 * 6) = 37ay.[/tex]
    Last edited by JeffM; 10-01-2013 at 03:17 PM. Reason: Fixed typo

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    Quote Originally Posted by JeffM View Post
    [tex]ax^2 + bx + c[/tex] is the standard form for a quadratic in one variable.

    A quadratic in standard form can be factored using the quadratic formula, but it pertains only to that special case.

    All factoring means is to restate an expression as a product of expressions. The most common way to do that is to look for common factors in the expression.

    Is your expression [tex]ay + a^6y^6?[/tex] If so, you should see that ay is a common factor and [tex]ay + a^6y^6 = ay(1 + a^5y^5).[/tex]

    If your expression is [tex]ay - a * 6 * y * 6,[/tex] then ay is again a common factor and [tex]ay - a * 6 * y * 6 = ay(1 + 6 * 6) = 37ay.[/tex]
    JeffM, small typo. I believe you meant ay(1 - 6 * 6) = -35ay
    "There are 10 types of people in this world - those who understand binary and those who don't."

  6. #6
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    Quote Originally Posted by srmichael View Post
    JeffM, small typo. I believe you meant ay(1 - 6 * 6) = -35ay
    I had a typo all right: original expression required plus sign not a minus sign. Thanks

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