*x*[FONT=MathJax_Main]2[/FONT][/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]14[/FONT][FONT=MathJax_Math]

*x*[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]49[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Math]

*y*

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- Thread starter ace7269
- Start date

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Why don't you provide an actual problem in its entirety and show what you have tried.x[FONT=MathJax_Main]2[/FONT][/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]14[/FONT][FONT=MathJax_Math]x[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]49[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Math]y

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By the way, you have given expressions, not equations. You factor expressions.

And it is quite feasible to factor the given expression: \(\displaystyle x^2 + 14x + 49 - y = (x + 7)^2 - y.\)

Okay, here is a full problem. Factor the expression [FONT=MathJax_Math]

Please trust me I have tried to work these out but I can't figure it out. Should I be using the ax^2 + bx + c expression? I just don't understand where to even start with these expressions. I'm not asking for anyone to do my homework I'm just trying to figure out these steps so I can do these kinds of problems on the exam tomorrow.

\(\displaystyle ax^2 + bx + c\) is the standard form for a quadratic in one variable.Okay, here is a full problem. Factor the expression [FONT=MathJax_Math]a[FONT=MathJax_Math]y[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Math]a[/FONT][FONT=MathJax_Main]6[/FONT][FONT=MathJax_Math]y[/FONT][FONT=MathJax_Main]6[/FONT][/FONT]. Simplify your answer as much as possible.

Please trust me I have tried to work these out but I can't figure it out. Should I be using the ax^2 + bx + c expression? I just don't understand where to even start with these expressions. I'm not asking for anyone to do my homework I'm just trying to figure out these steps so I can do these kinds of problems on the exam tomorrow.

A quadratic in standard form can be factored using the quadratic formula, but it pertains only to that special case.

All factoring means is to restate an expression as a product of expressions. The most common way to do that is to look for common factors in the expression.

Is your expression \(\displaystyle ay + a^6y^6?\) If so, you should see that ay is a common factor and \(\displaystyle ay + a^6y^6 = ay(1 + a^5y^5).\)

If your expression is \(\displaystyle ay + a * 6 * y * 6,\) then ay is again a common factor and \(\displaystyle ay - a * 6 * y * 6 = ay(1 + 6 * 6) = 37ay.\)

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JeffM, small typo. I believe you meant ay(1 - 6 * 6) = -35ay\(\displaystyle ax^2 + bx + c\) is the standard form for a quadratic in one variable.

A quadratic in standard form can be factored using the quadratic formula, but it pertains only to that special case.

All factoring means is to restate an expression as a product of expressions. The most common way to do that is to look for common factors in the expression.

Is your expression \(\displaystyle ay + a^6y^6?\) If so, you should see that ay is a common factor and \(\displaystyle ay + a^6y^6 = ay(1 + a^5y^5).\)

If your expression is \(\displaystyle ay - a * 6 * y * 6,\) then ay is again a common factor and \(\displaystyle ay - a * 6 * y * 6 = ay(1 + 6 * 6) = 37ay.\)

I had a typo all right: original expression required plus sign not a minus sign. ThanksJeffM, small typo. I believe you meant ay(1 - 6 * 6) = -35ay