Dear readers,
I am stuck with a question:
I have a square, with sides 2a. Ik want to make an equation similar to x^2 + y^2 = r^2 for a circle. Do you know if this is possible?
Thanks in advance,
Bram
Dear readers,
I am stuck with a question:
I have a square, with sides 2a. Ik want to make an equation similar to x^2 + y^2 = r^2 for a circle. Do you know if this is possible?
Thanks in advance,
Bram
For a square centered at the origin and that looks like a baseball diamond, you could refer to this (the 2nd and 4th diagrams down):
http://polymathprogrammer.com/2010/0...th-1-equation/
In the diagram, the c value is the length of the segment from the origin to a vertex.
A hypotenuse in the diagram will be square root of two multiplied by c, ** so c will be your 2a divided by the square root of two, or
[tex] a\sqrt{2}.[/tex]
Here is the equation:
[tex]|x| \ + \ |y| \ = \ a\sqrt{2}[/tex]
** [tex] \ \ \ [/tex] You may need to work this out to see this.
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