B bramplas New member Joined Sep 26, 2016 Messages 1 Sep 26, 2016 #1 Dear readers, I am stuck with a question: I have a square, with sides 2a. Ik want to make an equation similar to x^2 + y^2 = r^2 for a circle. Do you know if this is possible? Thanks in advance, Bram
Dear readers, I am stuck with a question: I have a square, with sides 2a. Ik want to make an equation similar to x^2 + y^2 = r^2 for a circle. Do you know if this is possible? Thanks in advance, Bram
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,250 Sep 26, 2016 #2 bramplas said: I am stuck with a question: I have a square, with sides 2a. Ik want to make an equation similar to x^2 + y^2 = r^2 for a circle. Do you know if this is possible? Click to expand... For a square centered at the origin and that looks like a baseball diamond, you could refer to this (the 2nd and 4th diagrams down): http://polymathprogrammer.com/2010/03/01/answered-can-you-describe-a-square-with-1-equation/ In the diagram, the c value is the length of the segment from the origin to a vertex. A hypotenuse in the diagram will be square root of two multiplied by c, ** so c will be your 2a divided by the square root of two, or \(\displaystyle a\sqrt{2}.\) Here is the equation: \(\displaystyle |x| \ + \ |y| \ = \ a\sqrt{2}\) ** \(\displaystyle \ \ \ \) You may need to work this out to see this.
bramplas said: I am stuck with a question: I have a square, with sides 2a. Ik want to make an equation similar to x^2 + y^2 = r^2 for a circle. Do you know if this is possible? Click to expand... For a square centered at the origin and that looks like a baseball diamond, you could refer to this (the 2nd and 4th diagrams down): http://polymathprogrammer.com/2010/03/01/answered-can-you-describe-a-square-with-1-equation/ In the diagram, the c value is the length of the segment from the origin to a vertex. A hypotenuse in the diagram will be square root of two multiplied by c, ** so c will be your 2a divided by the square root of two, or \(\displaystyle a\sqrt{2}.\) Here is the equation: \(\displaystyle |x| \ + \ |y| \ = \ a\sqrt{2}\) ** \(\displaystyle \ \ \ \) You may need to work this out to see this.
