A bad punter on a football team kicks a football approximately straight upward with an initial velocity of 61 ft/sec

[Cheetodust]

A) if the ball leaves his foot from a height of 3ft, write an equation for the vertical heigh s (in ft) of the ball t seconds after being kicked.
B) find the time(s) at which the ball is at a height of 49ft. Round to 1 decimal place
Please help? I can’t figure it out

 

[Deleted member 4993]

A) if the ball leaves his foot from a height of 3ft, write an equation for the vertical heigh s (in ft) of the ball t seconds after being kicked.
B) find the time(s) at which the ball is at a height of 49ft. Round to 1 decimal place
Please help? I can’t figure it out

Use the equation of projectile motion in constant gravity.

Please share your work and tell us exactly where you are stuck!

 

[Otis]

I can’t figure it out

Hi Cheetodust. Where did you get stuck? Are you using the correct value for acceleration due to gravity? (Don't use the metric-system value.)

\(\displaystyle s = -\frac{1}{2} \cdot g \cdot t^2 + v_0 \cdot t + s_0\)

s is ball's height at time t (feet)
g is gravitational constant near Earth's surface (feet per second per second)
t is elapsed time (seconds)
v₀ is ball's initial velocity (feet per second)
s₀ is ball's initial height (feet)



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