This is indeed annoying, but also fun. Note there are only three unmarried women.How many mixed hockey teams can be formed from six married couples, three spinsters and one bachelor if no wife will play without her husband? (A mixed hockey team = either five men and six women or six men and five women)
May I ask where you got the number 876?Thanks! I had thought it exactly as pka suggests: number of teams with 2 of the married women, with 3, with 4 with 5; then add all this up. With 2 married women you can only form 6C2 x 3C3 x 5C4 teams. With 3, just as pka suggested. With 4, it's 6C4 x (3C2 x 3C1 + 3C1 x 3C2). With 5: 6C5 x (3C1 x 5C0 + 1C1). All this should add up to 876, but I do not get THAT number!