A basic, but seemingly impossible, math problem I can't successfully solve. Can you please assist me?

JimB

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Joined
May 16, 2026
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Column A:
2
4
5
10
10
10
---
41

Column B
1
2
3
4
5
6
---
21
Column A consists of 6 individual numbers plus the total of those 6 numbers when added together. These 6 numbers, plus the total, must not be altered ever.
Column B consists of 6 individual numbers that can be altered. If you add these 6 numbers above it comes to 21. Obviously that total will need to be altered when any or all of the 6 numbers are changed.
Here's the challenge: For a successful solution I need to have any or all of the 6 numbers in Column B changed and then added together so they add up to a number that's 40 or less. Then I have to multiply those 6 individual numbers from Column B (changed or not) by the completely unchanged opposite number in Column A. All 6 of these now multiplied numbers must now "individually" be 42 or more after multiplication in order to successfully solve the problem (how much more doesn't matter").
 
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