A binomial times another binomial times a third binomial

[JASMINE_278]

I need help with this problem. (I have quite a few others just like it.)

(3p + 1)(3p - 1)(p + 2) :?:

Can someone please help? Thank you!

(3p + 1)(3p - 1)(p + 2)

(3p + 1)(3p - 1)
F.O.I.L IT OUT

9p2 + -3p +3p + -1
COMBINE LIKE TERMS

9p2-1
NOW DO F.O.I.L AGAIN AND FIND THE PRODUCT
(9p2-1)(p+2)
9p3+18p2-p-2

I THINK IVE GOTTEN IT NOW

 

[tkhunny]

Just multiply them.

How do you do this? 1234*567? Isn't it like this?

7*4 + 7*30 + 7*200 + 7*1000
plus
60*4 + 60*30 + 60*200 + 60*1000
plus
500*4 + 500*30 + 500*200 + 500*1000

See how each piece of one matches with each piece of the other, no matter how many pieces there are in either?

This is all you need to do. You should also remember that multiplication takes only two arguments. Split it up and tackle it one piece at a time.

 

[stapel]

I need help with this problem: (3p + 1)(3p - 1)(p + 2)

I have a feeling you can probably multiply any two of the factors, since they probably taught you "FOIL". Unfortunately, FOIL only applies for that one specific case: the product of two binomials. It doesn't help with general polynomial products.

To learn how to multiply polynomials in general, including how to multiply the product of 3p + 1 and 3p - 1 by p + 2, please study some of the many lessons available online:

. . . . .Google results for "polynomial multiplying"

Once you have studied a few lessons (at least two!), so you understand the basic terms and techniques, please attempt this exercise. If you get stuck, please reply showing all of your work and reasoning so far.

Thank you!

Eliz.

P.S. If you show your work "vertically", you'll probably want to use "Code" tags, so your formatting stays closer to what you intend.