A circus clown is fired from a cannon into a net that is situated 2.0 m above the cannon at some distance from it. The cannon is elevated at 50 degrees to the horionztal and the clown's speed at lunch if 15 m/s.
(a) Find the horizontal distance from the cannon where the net needs to be placed in order for the clown to land in it.
(b) Calculate the clown's velocity as he lands in the net
(a) To calculate the horizontal velcoity you do 15cos50 = 9.642 m/s
for the vertical velocity you do 15sin50 = 11.491 m/s
dv = vv1t + 1/2gt^2
-2 = 11.491t - 4.9t^2
4.9t^2 - 11.491t - 2 = 0
by using the quadratic formula you get
t = 6.345 s
subing the time into d = vt
d = 9.642(6.345)
d = 61.178 metres
(b) vv2^2 = vv1^2 + 2gdv
vv2^2 = 11.491^2 + 2(-9.8)(2)
vv2 = -9.6
v2^2 = vv1^2 + vv2^2
v2 = 15.3
tan theta = 9.6 / 9.642
theta = 45
the clowns velocity has he hits the net is 15.3 m/s [36 degrees E of S]
I am pretty sure I did part a right but I am not sure about part b.
(a) Find the horizontal distance from the cannon where the net needs to be placed in order for the clown to land in it.
(b) Calculate the clown's velocity as he lands in the net
(a) To calculate the horizontal velcoity you do 15cos50 = 9.642 m/s
for the vertical velocity you do 15sin50 = 11.491 m/s
dv = vv1t + 1/2gt^2
-2 = 11.491t - 4.9t^2
4.9t^2 - 11.491t - 2 = 0
by using the quadratic formula you get
t = 6.345 s
subing the time into d = vt
d = 9.642(6.345)
d = 61.178 metres
(b) vv2^2 = vv1^2 + 2gdv
vv2^2 = 11.491^2 + 2(-9.8)(2)
vv2 = -9.6
v2^2 = vv1^2 + vv2^2
v2 = 15.3
tan theta = 9.6 / 9.642
theta = 45
the clowns velocity has he hits the net is 15.3 m/s [36 degrees E of S]
I am pretty sure I did part a right but I am not sure about part b.