Yes that is what I have.....So you got [(5/6)/(1/10)] x (1/7)?
In the 'large' fraction multiply each of the four 'small' fractions by \(\displaystyle 30\) then combine the four results then multiply by one seventh.\(\displaystyle \dfrac{{\frac{2}{3} + \frac{1}{6}}}{{\frac{1}{5} - \frac{1}{{10}}}} \times \frac{1}{7}\)
the bottom is incorrect it should be 1/5 - 1/10In the 'large' fraction multiply each of the four 'small' fractions by \(\displaystyle 30\) then add the four results then multiply by one seventh.
Nevermind I got the 30 part...why am i multiplying by 30
CORRECTEDthe bottom is incorrect it should be 1/5 - 1/10
Have you been shown/taught to calculate "Lowest Common Multiple (LCM)"?why am i multiplying by 30
It is the LCD of the four so we have nice numbers.why am i multiplying by 30
Yes I have.. Just forget... So we multply by 30 and then we add them together and multiply by 1/7Have you been shown/taught to calculate "Lowest Common Multiple (LCM)"?
yeah I remembered the LCM thing...It is the LCD of the four so we have nice numbers.
Now do the fraction multiplication, like:so we have 25/3 * 1/7
Ok so did I do this correctly or did I miss something..It is the LCD of the four so we have nice numbers.
Nooooooo!Ok so did I do this correctly or did I miss something..
5/6 /1 5/6*1 = 5/6
5/6 / 10 = 5/60
5/60= 1/12
1/12 * 1/7
= 1/84
Is that correct or can I not do it that way
Nooooooo!
I don't know what you are doing.
In response #15 you had:
25/3 * 1/7 which was equal to: \(\displaystyle \frac{\frac{2}{3} \ + \frac{1}{6}}{\frac{1}{5} \ - \frac{1}{10}} \ * \ \frac{1}{7}\)
now:
25/3 * 1/7 converts \(\displaystyle \ \to \ \frac{25 * 1}{3 * 7}\)
can you complete it?
Nooooooo!
I don't know what you are doing.
In response #15 you had:
25/3 * 1/7 which was equal to: \(\displaystyle \frac{\frac{2}{3} \ + \frac{1}{6}}{\frac{1}{5} \ - \frac{1}{10}} \ * \ \frac{1}{7}\)
now:
25/3 * 1/7 converts \(\displaystyle \ \to \ \frac{25 * 1}{3 * 7}\)
can you complete it?