A logarithmic equation

[AlonBechor]

Here's the equation :

log(x^2 −1) = log^2(x−1)−log(x−4)

I've tried a few methods to solve this equation but got nothing out of them.
Could anybody give me a hint or some guidance on how this equation should be tackled.
Help would be really appreciated.
(^2 means squared).

 

[Deleted member 4993]

Here's the equation :

log(x^2 −1) = log^2(x−1)−log(x−4)

I've tried a few methods to solve this equation but got nothing out of them.
Could anybody give me a hint or some guidance on how this equation should be tackled.
Help would be really appreciated.
(^2 means squared).

Hint: Use:

log(A) = log(B) - log(C) \(\displaystyle \to \)

log[(A*C)/B] = 0

Please follow the rules of posting in this forum, as enunciated at:

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Please share your work/thoughts about this assignment. Tell us (show us) exactly where you are stuck. Otherwise we have to start with "definitions".

 

[Deleted member 4993]

Here's the equation :

log(x^2 −1) = log^2(x−1)−log(x−4)

I've tried a few methods to solve this equation but got nothing out of them.
Could anybody give me a hint or some guidance on how this equation should be tackled.
Help would be really appreciated.
(^2 means squared).

Does your problem look like this:

log(x^2 −1) = [log(x−1)]² − log(x−4)

or something else?

If it is the above equation, only way I can approximate the solution would be through Newton's method (numerical analysis)

 

[pka]

Here's the equation : log(x^2 −1) = log^2(x−1)−log(x−4)

SEE HERE, there are numerical solutions.
I greatly doubt that there in an algebraic solution exits.

 

[AlonBechor]

Thanks a lot guys !