Hello! Can anyone show that 2n+2-n/2=1+4n/2n+1? Thanks.
I edited it.Repost your problem - using parenthesis (grouping symbol), so that mathematical operations can be performed in correct order.
Hello! Can anyone show that (2n+2-n)/2=(1+4n)/2n+1? Thanks.
\(\displaystyle \text{Show that: }\:\dfrac{2^n + 2^{-n}}{2} \:=\:\dfrac{1+4^n}{2^{n+1}}\)
Thank you!Hello, Olsi!
\(\displaystyle \displaystyle \text{Multiply by }\frac{2^n}{2^n}\!:\quad \frac{2^n}{2^n}\cdot \frac{2^n + 2^{-n}}{2} \;=\;\frac{(2^n)(2^n) + (2^n)(2^{-n})}{(2^n)(2)} \;=\;\frac{4^n + 1}{2^{n+1}} \)