Absolute Ratio Test U-Sub

Silvanoshei

Junior Member
Joined
Feb 18, 2013
Messages
61
So when you have \(\displaystyle (x+1)^{2n+1}\) and you want to do your Un+1 to it, why does it come out to be \(\displaystyle (x+1)^{2n+3}\) and not \(\displaystyle (x+1)^{2n+2}\)?
 
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