Absolute Value

Joined
Oct 1, 2019
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3
Hi there!
So I have the problem |y-2| + 11 > 0, and I got, for my two solutions, |y| > -9 (which would mean all real numbers are true) and |y| < 13. How would I display my answer?

Thanks!
 

Dr.Peterson

Elite Member
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Nov 12, 2017
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Can you explain what you mean by "my two solutions"? Do you think both of these are correct answers, or that the answer consists of both combined by "or" or "and", or something else?

Also, can you show how you got them?

The correct answer is that the inequality is true for all real numbers, but the inequality |y-2| + 11 > 0 is not inherently equivalent to |y| > -9. I think you took an illegal step. The important part of answering your question will be to correct your work.
 
Joined
Oct 1, 2019
Messages
3
Can you explain what you mean by "my two solutions"? Do you think both of these are correct answers, or that the answer consists of both combined by "or" or "and", or something else?

Also, can you show how you got them?

The correct answer is that the inequality is true for all real numbers, but the inequality |y-2| + 11 > 0 is not inherently equivalent to |y| > -9. I think you took an illegal step. The important part of answering your question will be to correct your work.
Thanks! I realized I had a computation error, thus seeming like I took an "illegal step".
 

pka

Elite Member
Joined
Jan 29, 2005
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8,709
So I have the problem |y-2| + 11 > 0, and I got, for my two solutions, |y| > -9 (which would mean all real numbers are true) and |y| < 13. How would I display my answer?
Please think about the following:
If \(\displaystyle c>0\) then the solution to \(\displaystyle |x+5|+c>0\) has a solution set of \(\displaystyle (-\infty,\infty)\), all real numbers.
 

Dr.Peterson

Elite Member
Joined
Nov 12, 2017
Messages
5,056
Thanks! I realized I had a computation error, thus seeming like I took an "illegal step".
It will still be good to show your work, because I think there's more than just a wrong addition. Your result should not have looked anything like what you wrote. At the very least, you wrote absolute values where they should not have been.
 

Jomo

Elite Member
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Dec 30, 2014
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4,049
I agree with Dr P that you should show us your work as something went wrong somewhere. Thanks
 
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